Solving and Analyzing Differential Equations of the Form (2x^3y^2 - x^4y frac{dy}{dx} 0)
In the study of differential equations, it often becomes necessary to analyze and solve equations of various forms. One such form is the following:
[2x^3y^2 - x^4y frac{dy}{dx} 0]
Step-by-Step Solution
Let's proceed step-by-step to solve this differential equation.
Initial Equation
Starting with the given equation:
[2x^3y^2 - x^4y frac{dy}{dx} 0]
By rearranging the equation, we can simplify it:
[2x^3y^2 x^4y frac{dy}{dx}]
This can be further simplified as:
[2y - x frac{dy}{dx} 0]
Separation of Variables
To solve this, we can separate the variables (y) and (x) and integrate both sides:
[2 frac{dy}{y} -x frac{dx}{x}]
Integrating both sides, we get:
[2 ln|y| -ln|x^2| C]
This can be further simplified:
[2 ln|y| -2 ln|x| C]
Exponentiating both sides to solve for (y):
[y^2 e^{-2 ln|x| C}]
Using the property of exponents, we get:
[y^2 e^C cdot e^{-2 ln|x|}]
Since (e^C) is just a constant, we replace it with (A):
[y^2 A cdot |x|^{-2}]
This can be rewritten as:
[y^2 frac{A}{x^2}]
Therefore, the general solution is:
[y sqrt{frac{A}{x^2}} frac{sqrt{A}}{x}]
Alternative Approach
Another approach to solving the same differential equation is through direct separation:
[2x^3y^2 - x^4y frac{dy}{dx} 0]
Dividing through by (y cdot x^4), we get:
[ 2 frac{dx}{x} -frac{dy}{y}]
Integrating both sides:
[2 ln|x| -ln|y| C]
Which simplifies to:
[2 ln|x| ln|y| C]
Multiplying both sides by -1:
[-2 ln|x| - ln|y| -C]
This can be written as:
[ lnleft(frac{y}{x^2}right) C]
Exponentiating both sides:
[ y x^2 cdot e^C]
Since (e^C) is a constant, we can denote it as (A):
[y A x^2]
This is another general solution to the equation.
Special Case Solutions
It's also important to note the special solutions:
(x 0) (y 0)These are immediate solutions that can be derived from the original equation.
Conclusion
Thus, the general solutions of the differential equation (2x^3y^2 - x^4y frac{dy}{dx} 0) are:
[y frac{sqrt{A}}{x}] [y A x^2]where (A) is a constant. These solutions provide a comprehensive understanding of the behavior of the given differential equation.